In this rocket challenge, our goal was to solve for where our rocket would land within a 10% error rating by using calculated the average velocity and a new angle degree that we had not previously tested. We chose the 40 degree wooden block as our final, but tested with 30 and fifty degrees.
The following formula's were used throughout our challenge:
V=change in x/change in time
change in x=1/2at^2+vit
SOHCAHTOA
In order to gather data, we used a stopwatch, a rolling meter stick, and two wooden blocks which caused a 30 and fifty degree angle.
The above velocities are only the velocities in the horizontal position, not the vertical.
Then when we continue, to solve time we use the Xy = 1/2(a)t^2 + Viy(t) = 0= (0.5*-10)t^2+15.4t = 0=-5t^2+15.4t, where b is 15.4, and a is -5to solve for time, inputting it into the quadratic formula:
x = [-b ± √(b2 - 4ac)]/2a
t = [-15.4± √(-15.42 - 0)]/2(-5)
t = -30.6/-10
t = 3.082 s
So to find our final distance traveled, we can use vx=change in xx/change in time.
This becomes 12.25=delta (change in)x/3.6
to continue this concept, 3.082*12.25= 37.75 meters.
Our final data was that we were at 40.4 meters, and potentially attributed to either strong wind or miscalculations, resulting in a percentage error of (40.4-37.75)/40.4=6.5% error.
